Brewster Angle and Polarization Calculator
Find the angle at which reflected light is fully polarized, plus how much light reflects at any angle.
What it does
Light that bounces off a surface comes back partly polarized, and at one particular angle it comes back completely polarized. That angle is the Brewster angle, and it is the reason a polarizing film in sunglasses removes the glare from a wet road while leaving the rest of the scene alone.
OpenStax University Physics sets out the law. The reflected light is completely polarized at an angle of reflection given by the tangent of that angle equal to the ratio of the two refractive indices, and that angle is the Brewster angle, named after the nineteenth-century Scottish physicist who found it. The same section gives the recipe for the everyday case: light reflected at the Brewster angle could be completely blocked by a good polarizing filter held with its axis vertical.
The geometry behind it is simple. At the Brewster angle the reflected ray and the refracted ray are at ninety degrees to each other, which is why the page reports the angle of refraction next to the angle of incidence. The physics is a little subtler, and it is the reason the reflected light comes back polarized in one direction only: the vibration of the light in the plane of incidence does not match the vibration of the light in the second medium, so that component is not reflected at all.
This page computes the Fresnel reflectances for both components of the light at any angle of incidence, the angle of refraction, the total reflected fraction for unpolarized light and how strongly the reflected beam is polarized. It also reports the Brewster angle for the pair of media you choose, so you can see at a glance how far your incidence angle sits from it.
The model is for a smooth, flat interface between two smooth, non-absorbing media, which is why it does not describe a reflection off a scratched or dusty surface. It also assumes the light is incident from the denser medium onto the less dense one, or the other way round, in either case, since the law is written for the direction of travel and the page follows the ray.
How to use
- Pick the medium the light starts in and the medium it enters.
- Enter the angle of incidence, measured from the normal to the surface.
- Read the Brewster angle for that pair of media, which is where the reflected light is fully polarized.
- Read the angle of refraction, which follows from Snell's law at the angle you entered.
- Compare the two reflected fractions. The parallel component always reflects less than the perpendicular one, and it drops to zero at the Brewster angle.
- Read the polarization of the reflected beam. The closer your angle is to the Brewster angle, the more completely polarized the reflection is.
Formula
- theta B
- Brewster angle of incidence, in degrees.
- n1 and n2
- Refractive indices of the first and second medium.
- theta i
- Angle of incidence, measured from the normal.
- theta t
- Angle of refraction, measured from the normal.
- Rs and Rp
- Reflected fractions of the perpendicular and the parallel component.
The subscript s stands for the component perpendicular to the plane of incidence and p for the component parallel to it. At the Brewster angle the reflected and refracted rays are at right angles, so the two angles add to 90 degrees, and Rp is exactly zero there. The degree of polarization of the reflected beam assumes the incident light is unpolarized, which is what ordinary light is.
Worked example
Example: light from air onto glass at the Brewster angle
Defaults: air into glass at an angle of incidence of 56.63 degrees.
- Brewster's law gives the angle: tan(theta B) = 1.52 / 1.00, so theta B = 56.66 degrees.
- At that angle the refracted ray sits at 90 - 56.66 = 33.33 degrees, which the page confirms.
- The perpendicular component reflects Rs = 15.65 %.
- The parallel component reflects Rp = 0.00 %, because the incidence angle is the Brewster angle.
- Unpolarized light splits evenly between the two components, so the total reflected fraction is (15.65 + 0.00) / 2 = 7.82 %.
- The reflected beam is (15.65 - 0.00) / (15.65 + 0.00) = 100.0 % polarized, which is as complete as it can be.
- The tool shows 56.66 degrees, 33.33 degrees, 15.65 %, 0.00 %, 7.82 % and 100.0 %.
Reference table
| Light travels from | Light travels into | Brewster angle |
|---|---|---|
| Air | Water | 53.12 degrees |
| Air | Glass | 56.66 degrees |
| Air | Diamond | 67.52 degrees |
| Water | Glass | 48.75 degrees |
Limits
- The calculation is for a smooth flat interface between two smooth, non-absorbing media, so it does not describe rough or dusty surfaces.
- It assumes the incident light is unpolarized, which is the usual case but not the case for laser light or light that has already been through a polarizer.
- There is no absorption in either medium, so the transmitance is simply one minus the reflectance.
- Only a single interface is considered, so a coated lens or a stack of surfaces is out of scope.
Common mistakes
- Measuring the angle from the surface instead of from the normal. The Brewster angle for air to glass is 56.66 degrees from the normal, which is 33.34 degrees from the surface.
- Using the refraction angle as the Brewster angle. The Brewster angle is the angle of incidence.
- Expecting the reflected light to be polarized in the plane of incidence. The parallel component is the one that disappears, so what is left is polarized across it.
- Applying the law to light going from a dense medium to a less dense one and expecting the angle to disappear. The law still holds, but the angle is smaller and total internal reflection can intervene first.
- Forgetting that the polarization is a property of the reflected beam only. The refracted light is only partly polarized.
Try it yourself
Quick checks. Answers sit tucked under each question.
What is the Brewster angle for light going from air into glass?
56.66 degrees, from the tangent of the angle equal to 1.52. The tangent of 56.66 degrees is 1.5200, which is the ratio of the two refractive indices.
How much light is reflected at the Brewster angle?
7.82 % of unpolarized light. The perpendicular component reflects 15.65 % and the parallel component reflects nothing, and ordinary light carries equal amounts of each.
How completely polarized is the reflected light at 45 degrees from air to glass?
82.4 %. The perpendicular component reflects 9.67 % and the parallel component 0.94 %, so the difference over the sum gives 82.4 % polarization.
Questions
What is the Brewster angle?
The angle of incidence at which the reflected light is completely polarized. The tangent of that angle equals the ratio of the refractive indices of the two media.
Why is the light polarized at that angle?
The light vibrating in the plane of incidence does not match the vibration of the light in the second medium, so that component is not reflected. Only the perpendicular component comes back, which leaves a fully polarized beam.
How do polarizing sunglasses cut glare?
Glare off a road or a sheet of water is reflected light, and it is strongly polarized across the plane of incidence. A polarizing filter turned the right way blocks that component and leaves the scene in front of you alone.
Is the Brewster angle the same as the angle of refraction?
No. At the Brewster angle the reflected and refracted rays are at right angles, so the refraction angle is 90 degrees minus the Brewster angle.
What is Malus's law?
The rule that polarized light passing through a filter keeps a fraction of its intensity equal to the cosine squared of the angle between the polarization and the filter axis. It is the transmission counterpart of the reflectances on this page.
Does the Brewster angle exist for every pair of materials?
Yes, the law gives an angle for any pair of indices. What changes is how much light reflects there, which depends on how different the two indices are.
Sources
- OpenStax University Physics Volume 3, 1.7: polarization, Malus's law and Brewster's law
- Physics LibreTexts: polarization, Brewster's angle and the polarising glossary
- OpenStax College Physics 2e, 27.8: polarization by reflection